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Build Rock Paper Scissor Game Using Python

Writer's picture: Nihal ShahzNihal Shahz



Python is a multipurpose language and one can do literally anything with it. Python can also be used for game development. Let’s create a simple command line Rock-Paper-Scissor game without using any external game libraries like PyGame. In this game, user gets the first chance to pick the option among Rock, paper and scissor. After that computer select from remaining two choices(randomly), then winner is decided as per the rules. Winning Rules as follows : Rock vs paper-> paper wins Rock vs scissor-> Rock wins paper vs scissor-> scissor wins. In this game, randint() inbuilt function is used for generating random integer value within the given range. Below is the implementation :


# import random module

import random

# Print multiline instruction

# performstring concatenation of string

print("Winning Rules of the Rock paper scissor game as follows: \n"

+"Rock vs paper->paper wins \n"

+ "Rock vs scissor->Rock wins \n"

+"paper vs scissor->scissor wins \n")

while True:

print("Enter choice \n 1. Rock \n 2. paper \n 3. scissor \n")

# take the input from user

choice = int(input("User turn: "))

# OR is the short-circuit operator

# if any one of the condition is true

# then it return True value

# looping until user enter invalid input

while choice > 3 or choice < 1:

choice = int(input("enter valid input: "))

# initialize value of choice_name variable

# corresponding to the choice value

if choice == 1:

choice_name = 'Rock'

elif choice == 2:

choice_name = 'paper'

else:

choice_name = 'scissor'

# print user choice

print("user choice is: " + choice_name)

print("\nNow its computer turn.......")

# Computer chooses randomly any number

# among 1 , 2 and 3. Using randint method

# of random module

comp_choice = random.randint(1, 3)

# looping until comp_choice value

# is equal to the choice value

while comp_choice == choice:

comp_choice = random.randint(1, 3)

# initialize value of comp_choice_name

# variable corresponding to the choice value

if comp_choice == 1:

comp_choice_name = 'Rock'

elif comp_choice == 2:

comp_choice_name = 'paper'

else:

comp_choice_name = 'scissor'

print("Computer choice is: " + comp_choice_name)

print(choice_name + " V/s " + comp_choice_name)

# condition for winning

if((choice == 1 and comp_choice == 2) or

(choice == 2 and comp_choice ==1 )):

print("paper wins => ", end = "")

result = "paper"

elif((choice == 1 and comp_choice == 3) or

(choice == 3 and comp_choice == 1)):

print("Rock wins =>", end = "")

result = "Rock"

else:

print("scissor wins =>", end = "")

result = "scissor"

# Printing either user or computer wins

if result == choice_name:

print("<== User wins ==>")

else:

print("<== Computer wins ==>")

print("Do you want to play again? (Y/N)")

ans = input()

# if user input n or N then condition is True

if ans == 'n' or ans == 'N':

break

# after coming out of the while loop

# we print thanks for playing

print("\nThanks for playing")



Output : winning Rules of the Rock paper and scissor game as follows: rock vs paper->paper wins rock vs scissors->rock wins paper vs scissors->scissors wins Enter choice 1. Rock 2. paper 3. scissor User turn: 1 User choice is: Rock Now its computer turn....... computer choice is: paper Rock V/s paper paper wins =>computer wins do you want to play again? No


Thank You for reading till the end. Comment you queries if you have any doughts.


Credits- Nihalshahz

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